Question

please tell me answer fast of maths ​

Answer 1

Answer:

sin^4 q-cos^4 q= (sin^2q+cos^2q)(sin^2q-cos^2q)

=1×(sin^2q-cos^2q)

=1-cos^2q-cos^2q

=1-2cos^2q

diagonal =√(35)^2+(12)^2

cos =√(1-sin^2)=√{1-(11/61)^2}

cos 0=1

Let the side be s, then

s^2+s^2=(10√2)^2

2s^2=2×(10)^2

s^2=10^2

s=10

perimeter=4×10=40