Physics, asked by aarya66, 1 year ago

Please tell me answer fast tomorrow is my exam

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suhaa6: best of luck for your tomorrow exam
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Answers

Answered by Anonymous
4
if circuit is closed
effective resistance=
 \frac{10 \times 5}{10 + 5} +  \frac{5 \times 10}{10 + 5}   \\  =  \frac{50 + 50}{15}  \\  =  \frac{100}{15}  =  \frac{20}{3}
if circuit is open effective resistance
 =  \frac{15}{1 + 1}  =  \frac{15}{2}
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