Question

please tell me answer of question 6​

Answer 1

Answer:

root6+........

root6+x=x

x²-x+6=0

x²-3x+2x+6=0

x(x-3)+2(x-3)=0

x=3 is the answer of this question OK friend

Answer 2

Answer:

b)3

Let x=root 6+root 6........infinity

by squaring

x^2=6+root 6+root 6.....

x^2=6+x (substitute x = root 6+ root 6 … infinity)

x^2-x-6=0

x^2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x=3,x=-2

Since original equation have roots so x cant be negative, therefore , x=3

hope it helps u

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