please tell me answer of this
Attachments:

Answers
Answered by
0
Heres your answer
u=40 km per/h= 40×5/18=11.1 m per sec
v=0
a= -0.6 mere per sec^2
s=?
By using third equation of motion we can find distance ....

Hope it helps!!
u=40 km per/h= 40×5/18=11.1 m per sec
v=0
a= -0.6 mere per sec^2
s=?
By using third equation of motion we can find distance ....
Hope it helps!!
TiwariVaishnavi:
np
Similar questions
English,
9 months ago
Science,
9 months ago
Environmental Sciences,
9 months ago
Math,
1 year ago
History,
1 year ago