Question

Please tell me answer of this question in easy way but Step-by-step
the radius of a road roller is 84cm and its length is 1.4 M how much area of the ground will it press in 500 revolutions?

Answer 1

Hello friend


CSA of cylinder = 2πrh

h = 1.4 m
h = 1.4 × 100
h = 140 cm

r = 84cm

CSA of cylinder =
$2 \times \frac{22}{7} \times 84 \times 140 \\ 73920 {cm}^{2} \\ area \: of \: ground = curved \: surface \: area \: \times number \: of \: revolutions \\ \: = 73920 \times 500 \\ = 3696000 {cm}^{2} \\ \\ area \: of \: ground \: in \: metres = \frac{3696000}{10000 } \\ = 3696 {m}^{2}$


hope it helps