Math, asked by suhanisuryawanshi29, 1 year ago

Please tell me answer of this question in easy way but Step-by-step
quadrilateral ABCD is a rectangle l(AB) is 24 cm and l(BC) is 18 cm. A sector of radius 7 cm is cut off at each corner of the rectangle. what is the area of the remaining figure?

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Answers

Answered by knigam941
1
4 area of quadrant=
\pi{r}^{2}  \div 4
4 \times 22 \times 7 \times 7 \div 4  \times 7 = 154c {m}^{2}

area of rectangle=l×b
24×18=432cm^2
area of remaining pat=432-154=278

knigam941: is my answer right
Answered by arti9568
1
Area of rev-area of 4 sector
=24x18-22/7×7×7
=432-154
=278

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