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1) a = 1
d = 2-1 = 1
we have to find the sum upto 100
thus, we have n = 100
using formula:
Sn = n/2{2a+(n-1)d}
= 100/2{2×1+(100-1)×1}
= 50(2+99)
= 50×101
= 5050
2) a = 0.6
d = 1.7 - 0.6 = 1.1
we have to find the sum upto 100
thus, we have n = 100
using formula:
Sn = n/2{2a+(n-1)d}
=100/2{2×0.6+(100-1)1.1}
= 50(1.2+108.9)
=50×110.1
=5505
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