Question

please tell me fast............​

Answer 1

kx+2y=5,3x+y=1

since it has unique solution

a1/a2is not equal to b1/b2

k /3is not equal to 2/1

k " 6

therefore k could be any value other than 6

kx+3y=(k-3 ),12x+ky=k

a1/a2is not equal to b1/b2

k/12 " 3/k

k×k " 3×12

k " ±6

therefore k could be any Value other than ± 6

Hope this would help you