Math, asked by yashgeedker12, 7 months ago


please tell me fast​

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Answered by Anonymous
5

Answer:

(a) No real roots

Step-by-step explanation:

Give a quadratic equation such that,

2x^2 -3x +5 = 0

To know the nature of roots.

We know that,

Discriminant, D of a quadratic equation decides it's nature of roots.

For real and distinct roots, D > 0.

For real and equal roots, D = 0.

For imaginary roots, D < 0.

But, we know that,

D = b^2 - 4ac

Where, We have,

  • a = 2
  • b = -3
  • c = 5

Substituting the values, we will get,

=> D = (-3)^2 -4(2)(5)

=> D = 9 - 40

=> D = -31

Clearly, we have, D < 0

Hence, the correct option is (a) no real roots.

Answered by Anonymous
1

Given that ,

The polynomial is 2x² - 3x + 5

We know that , the discriminant of quadratic polynomial is given by

D = b² - 4ac

Thus ,

 \sf \mapsto D =  { (- 3)}^{2}  - 4 \times 2 \times 5 \\  \\ \sf \mapsto D =  9 - 40 \\  \\ \sf \mapsto D =   -  31 &lt; 0

 \therefore \sf \underline{The \:  given \:  quadratic \:  eq \:  has \:  unequal  \: and \:  imaginary  \: roots  \: (unreal  \: roots)}

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