Question

please tell me fast !​

Answer 1

Answer:

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Answer 2

y-1=0

y=1

Giving y=1 in the equation my-2y^2+y^3-4

0=m(1)-2(1)^2+(1)^3-4

0=m-2+1-4

0=m-6+1

m=6-1

m=5