Question

please tell me fast it's urgent​

Answer 1

Answer:

Clearly, the odd natural numbers from 1 to 150 are 1,3,5,...,149. 

This is an AP with first term a=1, common difference d=2 and last term an=149. 

Let there be n terms in this AP. 

Then,

an=149

⇒an=a+(n−1)d

149=1+(n−1)×2

149=1+2n−2

2n=150

∴n=75

∴ required sum =Sn=2n[an+1]=275[1+149]=5625

Answer 2

Happy New year dude............

May your all wishes come true.......,.(〃ﾟ3ﾟ〃)