Question

please tell me fast it's urgent​

Answer 1

Answer:

angle A is =60

B is= 90

then C =30

by sum of angles in triangl test..

ac=16

then bc will

sin 30=ac/bc

ac=greter than bc sin 30=16/2=/8

sin60=ab/bc

ab=greater than bc.

ab= 60 divide √3/2

Answer 2

Given:- angle A =60°

angle B =90°

side AC =16

To Find:- side AB & side BC

soln:- Angle A +B + C = 180......(angle sum property of a triangle)

60+90+ ANGLE C = 180

angle C = 30°

hence it's a 30°-60°-90° ∆

side opp. to 30° angle= ½× hypo(AC)

= ½× 16= 8

side opp.to 60°angle= √¾ × 16

= 4√3