Question

please tell me fast (x*4-y*4)​

Answer 1

Answer: Answer: ∴ $x^4 - y^4 = (x^2 + y^2)(x+y)(x-y)$

Step-by-step explanation:

Given:

$x^4 - y^4$

$= (x^2)^2 - (y^2)^2$

$= (x^2+y^2)(x^2-y^2) \\\\[When x^2 = a, y^2 = b, ... a^2-b^2 = (a+b)(a-b)$

Similarly,

$= (x^2+y^2)(x+y)(x-y)\\\\[x^2-y^2 = (x+y)(x-y)]$

Answer: ∴ $x^4 - y^4 = (x^2 + y^2)(x+y)(x-y)$

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Answer 2

Unable to understand your question, though answers to both the options are given below.

Answer:

If your question is: (x⁴ - y⁴),

The answer is as follows:

x⁴ - y⁴

= (x²)² - (y²)²

= (x² + y²) (x² - y²)

= [x² + y²] [(x + y) (x-y)]

= (x² + y²) (x + y) (x-y)

If your question is: [($x$ × 4) - (y × 4)]

The answer is as follows:

[($x$ × 4) - (y × 4)]

= [(4$x$) - (4y)]

= [ 4 ( x - y ) ]

Hope you understood both.

Thank You.