Question

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Answer 1

Step-by-step explanation:

in ΔABD and ΔADC

AB=AC(given)

∠ADB=∠ADC(=90°)

∠ABD=∠ACD(angles opp to equal sides are equal)

therefore ΔABD≅ΔADC

∠BAD=∠CAD(by cpct)

THEREFORE AD BISECTA ∠BAC

Answer 2

look at the attachment




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