Please tell me how to prove the problems (b) & (c)
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Answer:
in ∆BCD & ∆ABC, we have :-----
AB = DC (Given)
angle CBA = angle BCD (Given)
BC = BC (common)
so,
∆BCD ~ ∆ABC (SAS)
now,
angle BCA = angle CBD (By CPCT)
(Mark as brainlist)
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