please tell me its so urgent all questions answer
Attachments:
Answers
Answered by
0
for no.7 .......
by area of triangle = 1\2 ×base ×height
220=1\2×base ×11
220×2\1=base ×11
440=base ×11
440\11=base
40=base
for no.8
let,
the base =x
so,the height =2x
area of ∆= 1\2×base×height
400=1\2*x*2x
400*2\1=x*2x
800=2x square
800\2=x square
400= x square
√400=x
20cm.=x
so,base =20 and height =2*20=40 cm.
by area of triangle = 1\2 ×base ×height
220=1\2×base ×11
220×2\1=base ×11
440=base ×11
440\11=base
40=base
for no.8
let,
the base =x
so,the height =2x
area of ∆= 1\2×base×height
400=1\2*x*2x
400*2\1=x*2x
800=2x square
800\2=x square
400= x square
√400=x
20cm.=x
so,base =20 and height =2*20=40 cm.
belikebullet:
7. 40cm
8. B=20. H=40
9. H=20
Ok
how you got the ans.
give discription of que 8
I gave in the comment
Which one
I gave answer to this question separately, so in another comment box
9 problem explain
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
I can't understand
Which one
I can't understand full answer
Thank you
I understood
Similar questions