Question

please tell me please que no 2 please please please please please please please please please please please please please please please please please please please please please please please please please please​

Answer 1

$\bold{\red{(a+b)²=a²+b²+2ab}}$

$\bold{⇒(x+\dfrac{1}{x})²=x²+\dfrac{1}{x²}+2.\cancel{x}.\dfrac{1}{\cancel{x}}}$

$\bold{⇒(5)²=x²+\dfrac{1}{x²}+2(1)}$

$\bold{⇒x²+\dfrac{1}{x²}= 25-2}$

$\bold{⇒x²+\dfrac{1}{x²}= 23}$