Math, asked by Mahi7643, 2 months ago

please tell me pleasehelp​

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Answered by tyrbylent
0

Answer:

x_{1} = 6

Step-by-step explanation:

\left[\begin{array}{cc}1&x\\-x&-2\end{array}\right] = \left[\begin{array}{cc}5&-4\\1&-x\end{array}\right]

- 2 - (- x²) = - 5x - ( - 4)

x² + 5x - 2 - 4 = 0

x² + 5x - 6 = 0

x_{1} = 6 and x_{2} = - 1

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