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Question No. 9
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Step-by-step explanation:
Given :- Angle C = 100 degree and Angle D = 50 degree
Given :- Angle C = 100 degree and Angle D = 50 degree
Given :- Angle C = 100 degree and Angle D = 50 degree To find :- Measure of Angle P
Given :- Angle C = 100 degree and Angle D = 50 degree To find :- Measure of Angle PSol :-
We know that Measures of sum all angle of Quadrilateral is equal to 360 degree
Angle C = 100 degree ( Given )
Angle D = 50 degree ( -- )
Angles ( A + B + C + D = 360 )
150 + A + B = 360
A + B = 210 ------------ (I)
Now , In Triangle APB
A + B = 210 ------- ( From I )
Now Bisector of Angle A and B is dividing it ..
Therefore ..
A + B = 210/2 ( For Angle of Triangle APB )
A + B = 105 ------- ( From II )
Now ,
A + B + P = 180 ---- ( Measures of Angle of Triangle )
105 + P = 180
P = 75 Degree
Therefore Angle APB = 75 Degree
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