Question

please tell me right answer ​

Answer 1

Answer:

Explanation:

According to question,

$v_{c}$ ∝ $p^{a}$$r^{b}$$n^{c}$

$v_{c}$ = K $p^{a}$$r^{b}$$n^{c}$                  (where K is constant)

[$LT^{-1}$] = $[ML^{-3} ]^{a}$ $[L]^{b}$ $[ML^{-1}T^{-1}]^{c}$

[$LT^{-1}$] = $[M]^{a + c}$$[L]^{-3a + b - c}$$[T]^{-c}$

After comparing,

-c = -1

c = 1

a + c = 0

a + 1 = 0

a = -1

-3a + b - c = 1

(-3) x (-1) + b - 1 = 1

3 + b = 2

b = -1

We know that,

$v_{c}$ = K $p^{a}$$r^{b}$$n^{c}$                  (where K is constant)

$v_{c}$ = K $p^{-1}$$r^{-1}$$n$

$v_{c}$ =  $\frac{K n}{pr}$

Proved.

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