Question

please tell me right answer and fast...
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Answer 1

Answer:

x=3

Step-by-step explanation:

$\sqrt[3]{x-1}$ +$\sqrt[3]{x-3}$+$\sqrt[3]{x-5}$ = 0

$\sqrt[3]{x-1+x-3+x-5}$ = 0

$\sqrt[3]{3x-9}$ = 0

taking cube on both sides:

3x-9 = 0

3x = 9

x = 9/3

x = 3

Answer 2

Answer:

see the pic there is you answer