please tell me Section formula class 10th please it's urgent
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So, the coordinates of the point P(x, y) which divides the line segment joining the points A(x1, y1) and B(x2, y2), internally, in the ratio m1 : m2 are { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) } .This is known as the section formula.
Refer ExamFear video lessons for Proof
The mid-point of the line segment joining the points P(x1, y1) and Q(x2, y2) is [(x1+x2)/2 ,(y1+y2)/2]
Numerical: Find the coordinates of the point which divides the line segment joining the points (4, – 3) and (8, 5) in the ratio 3 : 1 internally
Solution: Using section formula P(x, y) = { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) }
We get P(x, y) = { (3*8 + 1*4 )/(3+1) , (3* 5 + 1 *-3)/(3+1) } = (7,3)
may it's helpful answer? add as brainleast please
Refer ExamFear video lessons for Proof
The mid-point of the line segment joining the points P(x1, y1) and Q(x2, y2) is [(x1+x2)/2 ,(y1+y2)/2]
Numerical: Find the coordinates of the point which divides the line segment joining the points (4, – 3) and (8, 5) in the ratio 3 : 1 internally
Solution: Using section formula P(x, y) = { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) }
We get P(x, y) = { (3*8 + 1*4 )/(3+1) , (3* 5 + 1 *-3)/(3+1) } = (7,3)
may it's helpful answer? add as brainleast please
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because it is diverting my mind from study
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