Question

Please tell me solution of question 7,8,9,10 and 13 please answer me tomorrow is my xam​

Answer 1

7.

$( \frac{3}{4} + \frac{2}{5} ) + ( \frac{6}{5} \times \frac{10}{3}) \\ = ( \frac{15 + 8}{20} ) + (2 \times 2) \\ = \frac{23}{20} + 4 = \frac{23 + 80}{20} \\ = \frac{103}{20}$

you can keep it in fractional form or you can also solve it further in decimal form

$= \frac{103}{20} = \frac{100 + 2 + 1}{20} \\ = \frac{100}{20} + \frac{2}{20} + \frac{1}{20} \\ = 5 + \frac{1}{10} + \frac{ \frac{1}{2} }{10} = 5 + 0.1 + \frac{0.5}{10} \\ = 5 + 0.1 + 0.05 \\ = 5.15$

8.

$\: \: \: \: \: \: \: \: \: \: \: 4 {m}^{2} - 3mn + 8 \\ (-) \: \: - {m}^{2} + 5mn \\ - - - - - - - - - - - - - - - - - - - - - \\ \: \: \: \: \: 4 {m}^{2} - ( - {m}^{2} ) - 3mn - ( + 5mn) + 8 - 0 \\ = 4 {m}^{2} + {m}^{2} - 3mn - 5mn + 8 \\ = 5 {m}^{2} - 8mn + 8$

9.

$\: \: \: \: \: \: 3 {x}^{3} - 5 {x}^{2} + 4x + 2 \\ + \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6 {x}^{2} - 9x - 8 \\ + \: \: \: 4 {x}^{3} - 2 {x}^{2} + 4x \\ + \: \: \: 4 {x}^{3} - {x}^{2} \: \: \: - 3x \\ - - - - - - - - - - - - - - - \\ = \: \: 11 {x}^{3} - 2 {x}^{2} + 14x - 6$

10.

$\frac{ {2}^{8} \times {3}^{4} }{8 \times {( - 2)}^{5} \times 27} \\ = - \frac{ {2}^{8} \times {3}^{4} }{ {2}^{3} \times {2}^{5} \times {3}^{3} } \\ = - \frac{ {2}^{8} \times {3}^{3} \times 3}{ {2}^{8} \times {3}^{3}} \\ = - 3$

13.

$\frac{p}{q} = {( \frac{2}{3}) }^{2} \div {( \frac{6}{7} )}^{0} = \frac{4}{9} \div 1 \: \\ (since \: {a}^{0} = 1) \\ \frac{p}{q} = \frac{4}{9} \\ {( \frac{p}{q} )}^{3} = {( \frac{4}{9} )}^{3} = \frac{64}{729}$

Answer 2

Answer:

13 Q) 64 / 729

10Q)  - 3

9Q) 11x^3+ 2x^2 - 5x -6

8 Q)  5m^2-2mn +8

7Q) 47/8

Step-by-step explanation:

13Q) Given (p/q) = (2/3)^2 +(6/7)^0

Hint: a^0 =1

(p/q)^3 = ((2/3)^2)^3

= (2/3)^6  [∵ ((a) ^m)^n = (a)^mn]

= 64 /729

10Q)  [{(2^8) ×(3)^4} / { 8×(-2)^5×27}] = ( -1) (2)^ (8-5-3) × (3)^(4-3)

=  - 3

9Q)  Adding like terms we get

x^3(3+4+4) +x^2(-5+6+2-1) +x(4 -9)+2-8

= 11x^3+ 2x^2 - 5x -6

8Q) 4m^2 + 3mn +8 -( -m)^2-5mn = 5m^2-2mn +8

7Q)  [ (3/4)÷(2/5) ]+ [ (6/5)×(10 /3)] = (3/4×5/2)×4 = 15/8 +4 = (15+32)/8 =47/8