Question

please tell me that answer in process ​

Answer 1

Given:- DA perpendicular to AB, CB perpendicular to AB and AC=BD

To prove:- triangle ABC and triangle BAD

Proof:-In triangle ABC and triangle BAD

AB=AB[ common side]

<DAB=<CBA[ right angle]

AC =BD[given]

Therefore triangle ABC and triangle BAD are concurrent by RHS postulate

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