please tell me that how value of y3 is ✓3/2
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Consider the masses be kept in a coordinate system with (m
1
=2kg) at the origin as follows:- [C is the centre of mass]
from geometry location of m
3
=(
2
1
,
2
3
)
from centre of mass formula
Xem=
m
1
+m
2
+m
3
m
1
x
1
+m
2
x
2
+m
3
x
3
Yem=
m
1
+m
2
+m
3
m
1
y
1
+m
2
y
2
+m
3
y
3
=
2+4+6
2×0+4×1+6×1
=
2+4+6
2×0+4×0+6
2
3
=
12
3
3
Xem=
12
7
⇒
4
3
∴ Location of centre of man =(
12
7
,
4
3
)
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