Question

please tell me that q ​

Answer 1

angle BCD=48°

Step-by-step explanation:

Given,angle abc=120°,angle cde= 108°

We draw a line df from the point d

angle abc= angle fgc (consecutive interior angles)

angle fgc = 120°

In triangle gcd...

angle fgc + angle cgd = 180° ( linear pair angle)

120°+angle cgd = 180°

angle cgd = 180°–120°

angle cgd = 60°

angle cde+angle cdg = 180° ( linear pair angles )

108°+angle cdg = 180°

angle cdg = 180°–108°

angle cdg = 72°

In triangle gcd

angle cgd + angle cdg + angle bcd = 180°

60°+72°+ angle bcd = 180°

132° + angle bcd = 180°

angle bcd = 180°–132°

angle bcd = 48°

answer is 48°

Answer 2

Answer:

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