please tell me the acid and show the solution also of all the question please help me I am just like your sister.
Answers
Answer:
For problem 1)
Take a number =x
Twice it = 2x
And subtract it from 10 gives 2
10-2x=2
-2x=2-10
-2x=-8
2x= 8
x=8/2=4 is the required number
For problem 2)
Take a number = x
Take One-eighth of that number = 1/8 x
According to question
1/8 x+ 6= 8
1/8 x = 8-6
1/8c =2
x= 2*8
x=16
For problem 3
Take a number = x
Take twice of it = 2x
According to question
2x/5=6
2x=5*6
2x=30
x= 30/2=15
For problem 4
The sum of two consecutive number is 21
Let's a take a number = x
The next number will be = x+1
According to question
x+(x+1)= 21
x+x+1=21
2x=21-1
2x=20
x=20/2=10
So
x= 10
x+1= 11
The two numbers are 10,11
For Q3 i
x-4=1
x=4+1=5. Chek it put x=5 5-4=1. 1=1
(ii) x+5= 3
x=3-5= - 2 check it
(iii) 2x+18=40
2x=40-18
2x=22
x= 22/2=11
Q2 (i)
x+ 8= 10
Put x= 1
1+ 8= 10
9=10
It is not true
Now put x=2
2+8=10
10=10
It is true so x=2
(ii) x-3=5
Put x= 2
2-3=5
-1=5
It is not true
Now put x= 8
8-3=5
5=5
It is true so x=8
{iii) 15-x=3
Put x= 10
15-10 =3
5=3
It is not true
Now put x=12
15-12=3
3=3
It is true so x=12