Question

please tell me the ans

4/x^-1+3y=2​

Answer 1

$\frac{4}{ {x}^{ - 1} } + 3y = 2 \\ = > \frac{ {x}^{ 1} }{4 } + 3y = 2 \\ = >3y = 2 - \frac{x}{4} \\ = > 3y = \frac{8 - x}{4} \\ = > y = \frac{8 - x}{4 \times 3} \\ = > y = \frac{8 - x}{12}$

• Hence, we got y value.

Now let's put that value again in that equation.

Answer 2

Ans of your 1 st q and 2nd q.