Question

please tell me the ans


aachi hu yushu didi​

Answer 1

2. (i) x² - 7x + k = 0

Given that 4 is the root if the quadratic equation x² - 7x + k = 0

p(4) = 4² - 7(4) + k = 0

16 - 28 + k = 0

- 12 + k = 0

k = 12

(ii) $\sf{x + \dfrac{35}{x} = 12}$

Taking LCM

⇒ $\sf{\dfrac{{x}^{2} + 35}{x} = 12}$

⇒ $\sf{x² + 35 = 12x}$

⇒ $\sf{x² + 35 - 12x = 0}$

⇒ $\sf{x² - 12x + 35 = 0}$

⇒ $\sf{x² - 7x - 5x + 35 = 0}$

⇒ $\sf{x (x - 7) - 5(x - 7) = 0}$

⇒ $\sf{(x - 5) (x - 7) = 0}$

⇒ $\sf{x - 5 = 0}$

⇒ $\fbox{\sf{x = 5}}$

⇒ $\sf{x - 7 = 0}$

⇒$\fbox{\sf{x = 7}}$

#NAWABZAADI

Answer 2

Step-by-step explanation:

yaha number 3 ka 1 and 2 ha

number 4 dena ha question post karo bestu jaldi