Question

please tell me the ans-----&&&

2&3​

Answer 1

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Answer 2

Height of pole=AB=8 m

Length of shadow of pole =BC=15 m

Length of shadow of tower=EF=45 m

In △ABC and △DEF

∠B=∠E=90° both 90° as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

$So, \: \frac{AB}{DE} = \frac{BC}{EF}$

$= > \frac{8}{DE} = \frac{15}{45}$

$= > 8 \times 3 = 24 \: cm$