Question

please tell me the answee​

Answer 1

$\frac{\frac{3}{7} z-\frac{1}{2}}{z-\frac{1}{4}} =\frac{2(6 z-7)}{7(4 z-1)}$

$\frac{2(6 z-7)}{7(4 z-1)}-\frac{3}{14}=\frac{1}{7}$

Finding the LCM

$7(4 z-1), 14,7=14(4 z-1)$

$\frac{2(6 z-7)}{7(4 z-1)} \cdot 14(4 z-1)-\frac{3}{14} \cdot 14(4 z-1)=\frac{1}{7} \cdot 14(4 z-1)$

$4(6 z-7)-3(4 z-1)=2(4 z-1)$

$14(6 z-7)-3(4 z-1)=12 z-25$

$2(4z-1)=8z-2$

$12z-25=8z-2$

Adding 25 on both sides

$12z-25+25=8z-2+25$

$12z=8z+23$

Subtracting both sides by 8z

$12z-8z=8z+23-8z$

$4z=23$

Dividing both sides by 4

$\frac{4z}{4}=\frac{23}{4}$

$z=\frac{23}{4}$

Final Answer: $z=\frac{23}{4}$ or $z=5.75$