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Explanation:
Here, we see that, there are 2 aluminium atoms, and hence, 2 moles of aluminium atoms in Al₂O₃ and hence, the total mass of Al₂O₃ is: 2x 27 +3 x 16= 102 g/mol
the total number of moles in 0.056g of Al₂O₃= 0.056/102 = 5.490 x 10⁻⁴ moles
now, the total number of Al ions= 2 x 5.490 x 10⁻⁴ moles x 6.023 x 10²³ ions
=> 6.61325 x 10²⁰ atoms
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