please tell me the answer
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Soln:-
=sin80°/cos10° + sin59° × sec31°
=sin80°/cos(90°-80°) + sin59° × 1/cos31°
[since (cos 90°-theta)=sin theta &
sec theta= 1/cos theta ]
=sin80°/ sin80° + sin 59° × 1/ cos (90°-59°)
=1 + sin 59° × 1/ sin 59°
[ since cos (90°- theta )=sin theta ]
=1+1
=2
HOPE IT WILL BE HELPFUL
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