please tell me the answer
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Answer:
113
Step-by-step explanation:
As we see that the x has a power of 3 so we begin by cubbing the whole equation.
So we start solving like:
[math]x + \dfrac{1}{x} = 3[/math]
[math](x + \dfrac{1}{x})^3 = 3^3[/math]
[math]x^3 + 3.x^2.\dfrac{1}{x} + 3.x.\dfrac{1}{x^2} + \dfrac{1}{x^3} = 27[/math]
[math](x^3 + \dfrac{1}{x^3}) + 3.x^2.\dfrac{1}{x} + 3.x.\dfrac{1}{x^2} = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + (3x + \dfrac{3}{x}) = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 3(x + \dfrac{1}{x}) = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 3 × 3 = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 9 = 27[/math]
[math]x^3 + \dfrac{1}{x^3} = 18[/math]
therefore answer is 113
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