Question

Please tell me the answer!​

Answer 1

Given : AB is a diameter

C is the centre

To prove : CP = CQ

Proof : In triangle PTC and triangle QTC

: CT = CT ( common side )

: angle PTC = angle QTC

( each 90°)

: PT = TQ

( Line perpendicular from the centre bisect the chord )

: triangle PTC congruent to triangle QTC

: CP = CQ ( by CPCT )

Step-by-step explanation:

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