Question

please tell me the answer​

Answer 1

Answer:

ii) in attachment

$iii) \frac{7\sqrt{6} - 22 }{ - 19}$

Step-by-step explanation:

$iii) \: \frac{2 \sqrt{3} - \sqrt{2} }{2 \sqrt{2} + 3 \sqrt{3} } = \frac{2 \sqrt{3} - \sqrt{2} }{2 \sqrt{2} + 3 \sqrt{3} } \times \frac{2 \sqrt{2} - 3 \sqrt{3} }{2 \sqrt{2} - 3 \sqrt{3}}$

$= \frac{4 \sqrt{6} - 18 - 4 + 3 \sqrt{6} }{ {(2 \sqrt{2}) }^{2} - {(3 \sqrt{3} )}^{2} }$

$= \frac{7\sqrt{6} - 22 }{8 - 27}$

$= \frac{7\sqrt{6} - 22 }{ - 19}$

$∴ Rationalised$

Answer 2

Answer:

1st Answer :- Above attachment

2nd Answer :-

$2 \sqrt{3} - \sqrt{2} \div 2 \sqrt{2} + 3 \sqrt{3}$

$2.04 \div 8.02 \\ \\ = 0.25$