Question

please tell me the answer​

Answer 1

Answer:

13.

Step-by-step explanation:

320

Given

a=10,n=16,d=6−10=−4

We know that

Sn=2n[2a+(n−1)d]

∴S16=216[2×10+(16−1)(−4)]

⇒S16=8[20+15(−4)]

⇒S16=8×(−40)

⇒S16=−320