Question

please tell me the answer​

Answer 1

Sides :- AB = PQ, BC = QR, AC = PR

angles :- angle A ≠ angle Q

Answer 2

Answer:

IN FIRST CASE

AB = QR

AND AS THE VALUE OF A=70°

AND VALUE OF Q=60°

So find out the value of one angle only

A=R...and B = Q

so as because of Equal value...it's will be

60°=70°

And the total value of 1.st triangle is

°•°=180°

And the value which we get in triangle is

70+60+x°=180

X°= 180-130°

so the value of C =50° in Triangle 1..

Now in 2nd case..

CA=RP

VALUE OF A=70

R=60°

AND

To find the value of CA =RP

THE VALUE OF Q IN 2ND TRIANGLE IS

=70°

AND AS BECAUSE OF A=P

P=70°

ANS SO THE VALUE OF

THIRD ANGLE IS ...X.

X+60+70=180

=50°

HENCE

LHS =RHS