Question

please tell me the answer​

Answer 1

Step-by-step explanation:

${( \frac{7}{4}) }^{3x - 2} = {( \frac{7}{4})}^{7} \times {( \frac{7}{4} )}^{3} \\ {( \frac{7}{4}) }^{3x - 2} = {( \frac{7}{4}) }^{7 + 3} \\ {( \frac{7}{4}) }^{3x - 2} = {( \frac{7}{4}) }^{10} \\ = > when \: the \: bases \: are \: same \: we \: equate \: powers \\ = > 3x - 2 = 10 \\ 3x = 10 + 2 \\ 3x = 12 \\ x = \frac{12}{3} \\ =x = 4$