Question

please tell me the answer​

Answer 1

Answer:

Let the natural number be x.

$160(x+12)=\frac{1}{x+12}$

$(x+12)^2=\frac{1}{160}$

$x+12=\frac{1}{4\sqrt{10} }$

$4x\sqrt{10} +48\sqrt{10}=1\\4x\sqrt{10} =1-48\sqrt{10} \\x =\frac{1-48\sqrt{10} }{4\sqrt{10} } \\x=\frac{\sqrt{10} }{40} -12$