Question

please tell me the answer​

Answer 1

Step-by-step explanation:

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So, ATQ we need to prove that MP = NP This can be done by proving that Triangle MBP is congruent to NBP

Let's do,

Angle MBP = Angle NBP (BO is bisector of ABC)

BP = BP (common)

Angle BMP = Angle BNP ( Both are equal to 90°)

Therefore, we can say Triangle MBP is congruent to NBP (ASA rule)

Hence, we can say MP = NP (CPCT)

In case you don't know

- ASA (Angle Side Angle )

- CPCT (Corresponding parts of congruent Triangles )