Question

please tell me the answer

Answer 1

(-a)^2 + (-b)^2 +(-c)^2 +2×-a×-b + 2×-b×-c + 2 × -a × -c = a^2+b^2+c^2 +2ab+2bc+2ac (Ans)

Answer 2

(-a - b - c)²

We know that (x + y + z)² = a² + b² + c² + 2xy + 2yz + 2xx

Here x = -a, y = - b, z = -c

By substituting the values given :

(a - b - c)² = (-a)² + (-b)² + (-c)² + 2(-a)(-b) + 2(-b)(-c) + 2(-a)(-c)

= a² + b² + c² + 2ab + 2bc + 2ac

=> (-a - b - c)² = a² + b² + c² + 2ab + 2bc + 2ac