Question

please tell me the answer asap I need this right now!!!!!!​

Answer 1

Answer:

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Step-by-step explanation:

$(\frac{-3}{11}) ^{x+5} \div (\frac{-3}{11}) ^{-2x+3} = (\frac{-3}{11}) ^{2x-5} \times [(\frac{-3}{11}) ^{-2}] ^ {x+4}\\\\(\frac{-3}{11}) ^{x+5 -(-2x+3)} = (\frac{-3}{11}) ^{2x-5} \times [(\frac{-3}{11}) ^{-2x-8}\\\\(\frac{-3}{11}) ^{3x+2} = (\frac{-3}{11}) ^{2x-5 + (-2x-8)}\\\\(\frac{-3}{11}) ^{3x+2} = (\frac{-3}{11}) ^-{13}\\\\On\:\: comparing \:\:both \:\:sides \:\:we \:\:get,\\\\3x+2 = -13\\\\3x =13-2\\\\3x = -15\\\\x = \frac{-15}{3}\\\\x = -5$