Question

please tell me the answer fast​

Answer 1

Answer:

26

Step-by-step explanation:

let the value of one digit number = x

let the value of two digit number = x-18

= x+9=x-18

x=26

Answer 2

Answer:

Original number = 36

Step-by-step explanation:

In the original two-digit number,

let x = digit in 1s place

let y = digit in 10s place

The number will be 10y + x

Also given, sum of digits = 9

=> x + y = 9 ...(i)

On interchanging the digits, the number will have y in 1s place and x in 10s place. The number will be 10x + y

According to the information given, when we subtract 18 from the interchanged number, it exceeds the original number by 9.

=> (10x + y) - 18 = (10y + x) + 9

=> 10x + y - 18 = x + 10y + 9

=> 9x - 9y = 27

=> x - y = 3 ............(ii)

Adding (i) and (ii), we get:

2x = 12

=> x = 6

Substituting for y in (i), we get:

6 + y = 9 => y = 3

Original number = 10y + x = 10*3 + 6 = 36

Interchanged number = 63

Verification:

Interchanged number less 18 = 63 - 18 = 45

We can see that this exceeds original number 36 by 9. (45 exceeds 36 by 9)

Hence, verified.