Math, asked by anushkanarwade, 13 days ago

please tell me the answer fast​

Attachments:

Answers

Answered by palrabin03
0

Answer:

this can we figured out through algebra.

let the denominator be x.

The numerator will be x-2.

The 2nd part of the question:

the equation will be \frac{x-2-2}{x+1} \\= \frac{1}{2} since two is subtacted

from numerator, 1 is added to denominator and the result is \frac{1}{2} .

let's solve the equation:

=> \frac{x-2-2}{x+1} \\= \frac{1}{2}

=> \frac{x-4}{x+1} =  \frac{1}{2}

=> \frac{x}{x+1} - 4 =  \frac{1}{2}

=> \frac{x}{x+1} =  \frac{1}{2} +4

=> \frac{x}{x+1} =  \frac{1}{2} + \frac{8}{2}

=> \frac{x}{x+1} =  \frac{9}{2}

=>\frac{x}{x} + \frac{1}{1} = \frac{9}{2}

=>\frac{x}{x} + \frac{x}{1}= \frac{9}{2}\\

=> \frac{x}{x} = \frac{9}{2}- \frac{x}{1}

=> 1 = \frac{9*1-2x}{2}

=>2 =\frac{9-2x}{2}

=> 4= 9-2x

=> 9-2x=4

=>-2x=4-9

=> -2x= - 5

=> 2x= 5

=> x= 2.5 or 2\frac{1}{2}

Thus, the fraction is 2\frac{1}{2}.

Please do mark me brainliest if this helps!

Similar questions