Math, asked by mdshafi123, 1 year ago

please tell me the answer fast

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Answers

Answered by jocelynbell
0

Answer:

x^3-4x^2+7x=x^2+3

Step-by-step explanation:

f=x^2-2x+4, f(x-1)=f(x+1):

Evaluating: f(x-1) x^2-4x+7=f(x-1)^2-2(x-1)+4

x(x^2-4x+7)=f(x+1)

Evaluating: f(x+1): x^2+3,=(x+1)^2-2(x+1)+4

x(x^2-4x+7)=(x^2+3)

x(x^2-4x+7)=(x^2+3): x^3-4x^2+7x=x^2+3


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