please tell me the answer fast
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Answer:
x^3-4x^2+7x=x^2+3
Step-by-step explanation:
f=x^2-2x+4, f(x-1)=f(x+1):
Evaluating: f(x-1) x^2-4x+7=f(x-1)^2-2(x-1)+4
x(x^2-4x+7)=f(x+1)
Evaluating: f(x+1): x^2+3,=(x+1)^2-2(x+1)+4
x(x^2-4x+7)=(x^2+3)
x(x^2-4x+7)=(x^2+3): x^3-4x^2+7x=x^2+3
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