Question

please tell me the answer in process​

Answer 1

Solution :-

in ∆BCA and ∆BPA we have,

→ CA = PA (given)

→ BC = BP (given)

→ BA = BA (common.)

therefore,

→ ∆BCA ≅ ∆BPA (By SSS congruence.)

As we know that, if the three sides of one triangle are equal to the three sides of another triangle, the triangles are congruent by SSS congruence.

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

https://brainly.in/question/16655884

Answer 2

The complete question is-

Prove that ΔBAC≅ΔBAP

Answer:-

Given

  AC = AP

   BC = BP

∠ABC = ∠ ABP

To Prove

Δ BAC ≅ Δ BAP

Proof

In Δ BAC and Δ BAP

AC = AP (Given)

AB = AB (Common)

BC = BP (Given)

Since all the three sides of a triangle are equal to the corresponding sides of the other triangle, given triangles are congruent by SSS (side side side) rule.

Hence Δ BAC ≅ Δ BAP (By SSS Congruency)