Math, asked by pradeepbhagat9227, 6 months ago

please tell me the answer it's too urgent

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Answers

Answered by krishnachouhan61
1

Step-by-step explanation:

verify the product = HCF x LCM

first find the product = 112 x 168 = 18816

let's find the LCM of 112 and 168

= 336

let's find the HCF of 112 and 168:

Hcf

112 = 2x2x2x2x7

168 =2x2x2x3x7

Hcf = 2x2x2x7

= 56

Hence, = 112 x 168 = 336 x 56

= 18816

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Answered by RvChaudharY50
0

Given :- for each pair of numbers , verify that their product = HCF * LCM .

  1. 112 , 168
  2. 156 , 364
  3. 270 , 45
  4. 380 , 1250

Answer 1):-

Prime factors of 112 and 168 :-

→ 112 = 2 * 2 * 2 * 2 * 7

→ 168 = 2 * 2 * 2 * 3 * 7

LCM = 2 * 2 * 2 * 2 * 3 * 7 = 336 .

HCF = 2 * 2 * 2 * 7 = 56 .

So,

→ Product of numbers = HCF * LCM

→ 112 * 168 = 336 * 56

→ 18816 = 18816 (Verified.)

Answer 2):-

Prime factors of 156 and 364 :-

→ 156 = 2 * 2 * 3 * 13

→ 364 = 2 * 2 * 7 * 13

LCM = 2 * 2 * 3 * 7 * 13 = 1092 .

HCF = 2 * 2 * 13 = 52 .

So,

→ Product of numbers = HCF * LCM

→ 156 * 364 = 1092 * 52

→ 56784 = 56784 (Verified.)

Answer 3):-

Prime factors of 270 and 45 :-

→ 270 = 2 * 3 * 3 * 3 * 5

→ 45 = 3 * 3 * 5

LCM = 2 * 3 * 3 * 3 * 5 = 270 .

HCF = 3 * 3 * 5 = 45 .

So,

→ Product of numbers = HCF * LCM

→ 270 * 45 = 270 * 45

→ 12150 = 12150 (Verified.)

Answer 4):-

Prime factors of 380 and 1250 :-

→ 380 = 2 * 2 * 5 * 19

→ 1250 = 2 * 5 * 5 * 5 * 5

LCM = 2 * 2 * 5 * 5 * 5 * 5 * 19 = 47500 .

HCF = 2 * 5 = 10 .

So,

→ Product of numbers = HCF * LCM

→ 380 * 1250 = 47500 * 10

→ 475000 = 475000 (Verified.)

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