Question

please tell me the answer of 17 no...​

Answer 1

In ∆s ABD and ABC

▶️∆ABD = ABC ( common )

∆ABD = ∆BAC = 90⁰

∆BAD = ∆ACB ( Sum of angles for a ∆ = 180⁰ )

∆ABD ~ ∆CBA

$\frac{ab}{cb} = \frac{bd}{ba} = \frac{ad}{ca}$

$= \frac{5}{13} = \frac{ad}{12} = ad = \frac{12 \times 5}{13} = \frac{60}{13} cm$

In

$abc = \frac{1}{2} b.h = \frac{1}{2} \times 5 \times 12 = 30cm$

Hope it help you.