Question

please tell me the answer of that parts which i have ticked? ​

Answer 1

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3+x=4x-3

3+3=4x-x

6=3x

$\sf \cancel\frac{6}{3} = x$

2=x

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8x+1=15+x

8x-x=15-1

7x=14

$x = \cancel\frac{14}{7}$

x=2

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Answer 2

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❥︎ Given :

➜ $3 + x = 4x - 3$

➜ $8x + 1 = 15 + x$

❥︎ To find :

The value of x

❥︎ Solution :

➜ $3 + x = 4x - 3$

⇒ $3 + 3 = 4x - x$

⇒ $6 = 3x$

⇒ $x = \frac {6}{3}$

⇒ $x = 3$

$\therefore \textbf {Hence, the value of x is 3.}$

➜ $8x + 1 = 15 + x$

⇒ $8x - x = 15 - 1$

⇒ $7x = 14$

⇒ $x = \frac {14}{7}$

⇒ $x = 2$

$\therefore \textbf {Hence, the value of x is 2.}$

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